COMMON-COLLECTOR AMPLIFIER


The common-collector amplifier shown below contains an emitter resistor but the collector is connected directly to the positive rail. The base is biased by 2 resistors. Supposing that
·       the quiescent emitter current is about 1 mA,
·       the voltage present across the emitter-resistor R3 is 7.5 Volt,
·        bringing the output to exactly half-way between the supply rails.
·       To provide for a vBE of 0.7 V, it needs to hold base at 8.2 V.
·       The values of R1 and R2are calculated to provide this.

Read More!

WIEN BRIDGE OSCILLATOR


The WIEN BRIDGE OSCILLATOR (figure shown below) largely relies on a pair of LR resonant networks for shifting the output signal by exactly 180 degree and one particular frequency. Then this phase-shifted signal is fed back to the non-inverting (1) input of the op amp. It is amplified and add force to the output signal. A strong sinusoidal waveform is generated. In Wien network, the two capacitors and both od the resistors are equal in value. The signal frequency is f = 1/2Ï€RC.

The benfit of using the amplifier is that it is easily made tunable by making use of a dual ganged variable resistor for the 2 resistors in the Wien network.
Read More!

PROPORTIONAL-INTEGRAL CONTROL


The proportional-integral (PI) controller make use of an integrating block to produce a signal which is integral over time of the error signal. The output value of the integrator is zero for beginning.
Read More!

CROSS OVER DISTORTION


A normally used technique for the purpose of eliminating crossover distortion is by way of biasing the transistors so that they are on the point of conducting. With BJTs, this would mean the biasing them so that vBE is equal to 0.7 V when there is no signal. The very easy way to do all this is to making use of the 0.7 V voltage level drop across a forward-biased diode. In the circuit diagram shown below, current flows through the chain that contains R1, D1, D2 and R2.
Read More!

CROSSTALK



When the several lines come close to each together, the current flowing across one line may have the effect of causing current flow in one or more than one adjacent lines. This may be due to the characteristics of capacitance between the two lines or there may be effect of inductance. The effect is refers to as crosstalk, and this effect often occurs in multi cored cables and it also occurred in the ribbon cables that are used for connecting computers to peripheral devices. This effect may be eliminated in multi-cored cables by way of having each of the cores enclosed in a separate earthed shield, although due to this reason the cable is considerably more expensive.

By connecting two alternate lines to ground somewhat enables us to reduce crosstalk in ribbon cables. The crosstalk process also happens between adjacent tracks on the same circuit boards, especially when the tracks run side-by-side for substantial distances. This is normally avoided by running grounded tracks between the active ones. The magnitude of the current induced by a magnetic field is directly proportional to the variation rate of the magnetic flux. This in turn is proportional to the rate of change of the current generating the field. So here we come to know that, the induced crosstalk is more serious at higher frequency level.

The effect is the identical as for the capacitative crosstalk because there is decrease incapacitance with frequency and high-frequency signals pass more gladly through the capacitative barrier.

The pulses in data signaling at high rates have very rapid rise-times, and all of these result in the most serious crosstalk problems. Spikes several volts high might be induced on an adjacent line at the beginning and end of each pulse. The effect can entirely disrupt the signal that is on the adjacent line. We can adjust the rise time with many kinds of line driver so that it is no more rapid than necessary, and as a result the effect of crosstalk is minimized.
Read More!

COLPITTS OSCILLATOR


The type of oscillator we are discussing in this tutorial largely depends on a resonant network that consists of 2 capacitors (series capacitance is equal C in total) and an inductor (L) connected in parallel with them. This L-C network resonates at a frequency, f = 1/2 π(LC)-1/2. The op amp is wired in the circuit as an inverting amplifier with a gain of about 30. Its non-inverting (1) input is kept at half the supply voltage (1V/2) by the two 22 kΩ resistors that are acting as a potential divider. The LC network is placed in the +ve feedback loop of the op amp. At the resonant frequency level the output coming from the op amp makes the network to resonate. The tapped point between the capacitors exists at 1V/2, but the part of the oscillating signal across C2 is fed to the inverting amplifier. It is then amplified and maintains the network oscillating strongly.
Read More!

Phase shift oscillator


First thing to know is that all three oscillators depend on +ve feedback to keep them oscillating. Some part of the output produced by the op amp is required to be fed back to its non-inverting input to keep itself in the oscillations.

The voltage level at the +ve terminal of the op amp is kept constant at half the supply, and stabilized by making use of capacitor.

A rising voltage at the output is fed back to the inverting inputs (2) that as a result cause a fall of output. This is +ve feedback and the op amp would have as table output. Also there is +ve feedback across the phase shift network.
Read More!

Relative and absolute voltages




 
Read More!

 
Design by Wordpress Theme | Bloggerized by Free Blogger Templates | coupon codes